# How do you solve #2^x = 7#?

##### 1 Answer

Mar 16, 2016

#### Explanation:

#2^x=7#

#log(2^x)=log(7)#

#xlog(2)=log(7)#

#x=log(7)/log(2)#

#color(green)(|bar(ul(color(white)(a/a)x~~2.81color(white)(a/a)|)))#